2x^2-12x-130=-64

Solution for 2x^2-12x-130=-64 equation:

2x^2-12x-130=-64

We move all terms to the left:

2x^2-12x-130-(-64)=0

We add all the numbers together, and all the variables

2x^2-12x-66=0

a = 2; b = -12; c = -66;
Δ = b2-4ac
Δ = -122-4·2·(-66)
Δ = 672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{672}=\sqrt{16*42}=\sqrt{16}*\sqrt{42}=4\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{42}}{2*2}=\frac{12-4\sqrt{42}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{42}}{2*2}=\frac{12+4\sqrt{42}}{4}
$